Created
October 11, 2020 14:09
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FESTIVAL 정답 코드
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#include<iostream> | |
using namespace std; | |
int borrowCost[1000]; | |
int main(){ | |
int numTest; | |
int maxDays,numTeam; | |
double minCost; | |
double divResult; | |
cin>>numTest; | |
for(int i=0; i <numTest ; ++i){ | |
cin>>maxDays>>numTeam; | |
for(int j=0; j<maxDays ; ++j) | |
cin>>borrowCost[j]; | |
minCost = 100; //모든 비용은 100이하이므로 100이 평군의 최대값 | |
for(int j = numTeam; j<=maxDays ; ++j){ | |
double sum = 0; | |
for(int k=0; k<j ; ++k) | |
sum += borrowCost[k]; //일단은 0~j-1까지 더해둠 | |
divResult = sum/j; | |
minCost = minCost < divResult ? minCost: divResult; | |
for(int starIdx=j; starIdx< maxDays ; ++starIdx){ | |
sum -= borrowCost[starIdx-j]; //가장 앞의 수를 빼주고 | |
sum += borrowCost[starIdx]; //그 뒤 차례의 수를 더해줌 | |
divResult = sum/j; | |
minCost = minCost < divResult ? minCost: divResult; | |
} | |
} | |
printf("%.11f\n",minCost); | |
} | |
return 0; | |
} |
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