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          March 8, 2018 00:45 
        
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  | import java.util.Optional; | |
| import java.util.function.Function; | |
| class Main { | |
| public static void main(String[] args) { | |
| Optional<String> o = Optional.of("foo"); | |
| Function<String, String> f = s -> null; | |
| Function<String, String> g = String::valueOf; | |
| //lawless lolz | |
| System.out.println( o.map(g.compose(f)) ); //Optional[null] | |
| System.out.println( o.map(f).map(g) ); //Optional.empty | |
| //This is because | |
| System.out.println( o.map(f) ); //Optional.empty | |
| //Once again for clarity | |
| System.out.println( o.map(s -> null) ); //Optional.empty | |
| //And now for more lolz | |
| System.out.println( o.flatMap(s -> null) ); //throws NullPointerException | |
| } | |
| } | 
FWIW, we tried this (failed) experiment about 12 years ago. The correct solution is to assume that null does not exist, at all.
  
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That's correct.
Optionalhas been designed to explicitly never be able to contain anullvalue. Arguably more correct behaviour would have been to havemapto throw anNPEif the function application returnednull- but you'd still have the issue thato map f map gando map (g compose f)would be different.Presumably one "advantage" for explicitly disallowing
Optional(null)might raise its head when the JVM gets value classes.