A little JS [ES3] task: In each case, implement `x` so that the expression is true. Do not modify the expressions though. Post your solutions as a fork of this gist. ***Remember: ES3 only.

1.js

/x/==x

2.js

x() === x()() === x()()()

3.js

x > 2 && x < 2

4.js

delete x.a && x.a;

5.js

x[x]==x

6.js

typeof new x < typeof x

7.js

x - 1 === x + 1

typeof typeof x === 'string'

ES3 only. Don't cheat. :)

Late, but done :)

It took some time =) Nice stuff! https://gist.github.com/lushchick/5016434

Nice quiz
expression with delete still didn't solved

Couldn't find #4 and #6: https://gist.github.com/vjeux/5022831

var x = Infinity;
x - 1 === x + 1;