Created
January 8, 2011 05:47
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PHP for parsing the JSON output a published Google spreadsheet and displaying columns from each row.
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<?php | |
// Parsing this spreadsheet: https://spreadsheets.google.com/pub?key=0Ah0xU81penP1dFNLWk5YMW41dkcwa1JNQXk3YUJoOXc&hl=en&output=html | |
$url = 'http://spreadsheets.google.com/feeds/list/0Ah0xU81penP1dFNLWk5YMW41dkcwa1JNQXk3YUJoOXc/od6/public/values?alt=json'; | |
$file= file_get_contents($url); | |
$json = json_decode($file); | |
$rows = $json->{'feed'}->{'entry'}; | |
foreach($rows as $row) { | |
echo '<p>'; | |
$title = $row->{'gsx$title'}->{'$t'}; | |
$author = $row->{'gsx$author'}->{'$t'}; | |
$review = $row->{'gsx$review'}->{'$t'}; | |
echo $title . ' by ' . $author . '<br>' . $review; | |
echo '</p>'; | |
} | |
// See this here: http://imagine-it.org/google/spreadsheets/showspreadsheet.php | |
?> |
hey there,
just came across this feature i want to experiment with myself.
could you perhaps show how you would add a 4th entry, for example $genre = $row->{'gsx$genre'}->{'$t'};
and group the rows by genre?
(so they would all sit in the same div from the echo)
thank you!
V3 of the API will go away later this year, V4 is much easier to use, but needs an API Key
<?php
$url = 'https://sheets.googleapis.com/v4/spreadsheets/{sheetId}/values/{sheetName}?key={API_KEY}';
$json = json_decode(file_get_contents($url));
$rows = $json->values;
foreach($rows as $row) {
var_dump($row);
}
https://gist.github.com/marcus-at-localhost/1886c1f35647ff682752c19880bd9dd1
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When i run this program it give me an error, can you please tell me any solution
Error are:
Notice: Trying to get property 'feed' of non-object in D:\xampp\htdocs\spreadsheet\test.php on line 5
Notice: Trying to get property 'entry' of non-object in D:\xampp\htdocs\spreadsheet\test.php on line 5
Warning: Invalid argument supplied for foreach() in D:\xampp\htdocs\spreadsheet\test.php on line 6