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November 1, 2015 21:10
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#!/usr/bin/env python2.7 | |
#conflict-free strings using python and numpy | |
#Marios Papachristou: [email protected] | |
import numpy as np | |
import time | |
def generate_conflict_free_string(n, f = lambda x: x): | |
k = n / 2 | |
a = np.zeros(n) | |
for i in range(1, n / 2): | |
a[k + i] = f(i) | |
a[k - i] = f(i) | |
a[0] = f(k - 2) | |
if n % 2 != 0: | |
a[n-1] = a[0] | |
return a | |
def generate_permutations(s): | |
result = [] | |
k = len(s)/2 | |
for i in range(k): | |
result.append(np.mod(s + i,k)) | |
return result | |
def generate_permutation_array(n, f = lambda A:A): | |
S = generate_conflict_free_string(n) | |
P = generate_permutations(S) | |
A = np.array(map(lambda x: list(P[x].astype(int)), list(S.astype(int)))) | |
return f(A) | |
if __name__ == '__main__': #an example | |
N = 40 | |
T = [] | |
for x in range(N): | |
t = time.time() | |
A = generate_permutation_array(x+2) | |
print A | |
T.append(time.time() - t) | |
print 'Elements: {0}, Time elapsed: {1} sec'.format(x+2, T[x]) |
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