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class Solution(object): | |
def getProbability(self, balls): | |
""" | |
:type balls: List[int] | |
:rtype: float | |
""" | |
trie = {} | |
newballs = balls + balls[0:-1] | |
perBall = [] | |
stack = [] | |
for x in range(0, len(balls)): | |
stack.append([[],len(perBall)]) | |
perBall += [x+1 for _ in range(balls[x])] | |
newSeqList = [] | |
# DFS and create set of balls in box 1 which are uniq. | |
# We do one box because, box 2 values can be induced by box 1 | |
# Uniq in the sense that the order doesn't matter only the amount of ball matter | |
# [1,1,2] and [1,2,1] values in box 1 are considered same | |
# [1,1,2] and [1,1,1] values in box 1 are considered different | |
while stack: | |
theSeq, newPointer = stack.pop() | |
theSeq.append(perBall[newPointer]) | |
if len(theSeq) == (len(perBall) /2): | |
newSeqList.append(theSeq) | |
continue | |
prev = None | |
for i in range(newPointer, len(perBall) - 1): | |
# Make new copy for the new seq | |
newSeq = theSeq[:] | |
if prev == None or prev != perBall[i + 1]: | |
stack.append([newSeq, i+1]) | |
prev = perBall[i + 1] | |
for x in newSeqList: | |
print('- ' + str(x)) | |
s = Solution() | |
balls = [1,2,1] | |
# balls = [3,2,1] | |
s.getProbability(balls) | |
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