part2.py

a = [0x2a,0x7c,0x2d,0x49,0x66,0x6e,0x71,0x32,
	 0x30,0x21,0x20,0x0a,0x41,0x5a,0x64,0x24,
	 0x72,0x3c,0x58,0x6f,0x5c,0x44,0x2f,0x7b,
	 0x4b,0x43,0x7e,0x61,0x34,0x54,0x7a,0x37,
	 0x29,0x59,0x5e,0x3a,0x78,0x60,0x0b,0x7d,
	 0x53,0x73,0x31,0x79,0x4f,0x6d,0x69,0x76,
	 0x23,0x0d,0x25,0x5d,0x40,0x5b,0x5f,0x4e,
	 0x28,0x48,0x6a,0x2c,0x56,0x51,0x75,0x67]

	 	 
finals = [
0x34,0x60,0x51,0x25,0x41,0x5f,0x41,0x23,
0x54,0x3a,0x5a,0x25,0x41,0x2f,0x48,0x7d,
0x7b,0x25,0x6d,0x53,0x41,0x5b,0x51,0xb,
]


import string
import itertools

alphabet = string.ascii_lowercase + string.digits + '_+'

def find_chars(finals):
	#print(finals)
	for x,y,z in itertools.product(string.printable, repeat=3):
		if finals[0] != a[ord(x) >> 2]:
			continue
		second = (ord(y) >> 4) | ((ord(x) & 3) << 4)
		if finals[1] != a[second]:
			continue
		third = (ord(z) >> 6) | ((ord(y) & 0xf) << 2)
		if finals[2] != a[third]:
			continue
		if finals[3] != a[(ord(z) & 0x3f)]:
			continue

		return ''.join([x,y,z])
flag = []
for i in range(len(finals)/4):
	flag.append(find_chars(finals[i*4:(i+1)*4]))

print(''.join(flag))