Created
January 21, 2013 13:34
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Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example,
Given 1->2->3->3->4->4->5, return 1->2->5.
Given 1->1->1->2->3, return 2->3. http://leetcode.com/onlinejudge#question_82
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| /** | |
| * Definition for singly-linked list. | |
| * struct ListNode { | |
| * int val; | |
| * ListNode *next; | |
| * ListNode(int x) : val(x), next(NULL) {} | |
| * }; | |
| */ | |
| class Solution { | |
| public: | |
| ListNode *deleteDuplicates(ListNode *head) { | |
| ListNode* ret = head; | |
| ListNode* prev = NULL; | |
| ListNode* cur = head; | |
| while (cur != NULL) { | |
| int cnt = 0; | |
| int val = cur->val; | |
| while (cur != NULL && cur->val == val) { | |
| cur = cur->next; | |
| cnt++; | |
| } | |
| if (cnt == 1) { | |
| ret->val = val; | |
| prev = ret; | |
| ret = ret->next; | |
| } | |
| } | |
| if (prev != NULL) | |
| prev->next = NULL; | |
| else | |
| head = NULL; | |
| return head; | |
| } | |
| }; |
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