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July 20, 2026 11:24
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Claim: The Dixmier conjecture is false in rank 3.
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| Claim: The Dixmier conjecture is false in rank 3. | |
| Let A_3 = C<x,y,z,Dx,Dy,Dz> be the third Weyl algebra. Define phi on x,y,z by | |
| phi(x) = (1+xy)^3 z + y^2(1+xy)(4+3xy) | |
| phi(y) = y + 3x(1+xy)^2 z + 3xy^2(4+3xy) | |
| phi(z) = 2x - 3x^2y - x^3z. | |
| Let F = (phi(x),phi(y),phi(z)), and define | |
| phi(D_i) = sum_k (J_F^{-1})_{ki} D_k. | |
| Here det(J_F) = -2, so J_F^{-1} has polynomial entries and phi is an endomorphism of A_3. It is injective because A_3 is simple. | |
| It is not surjective: F is not injective, since | |
| F(0,0,-1/4) | |
| = F(1,-3/2,13/2) | |
| = F(-1,3/2,13/2) | |
| = (-1/4,0,0). | |
| Moreover, the centralizer of phi(x), phi(y), phi(z) in A_3 is C[x,y,z]. Hence, if phi were an automorphism, then | |
| C[x,y,z] = C[phi(x),phi(y),phi(z)], | |
| which would make F a polynomial automorphism, contradicting the displayed non-injectivity. | |
| Therefore phi is an injective, non-surjective endomorphism of A_3, giving a counterexample to the Dixmier conjecture in rank 3. |
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