perpetual-hydrofoil · January 19, 2023 01:35 · perpetual-hydrofoil · Sep 26, 2011 · nicolewiggins · Dec 12, 2014
diff --git a/unfollow.py b/unfollow.py
 #! /usr/bin/env python

 # how to unfollow everyone who isn't following you
 # By Jamieson Becker (Public Domain/no copyright, do what you will)

 # Easy instructions, even if you don't know Python
 #
 # 1.  Install pip (apt-get install python-pip) and then
 #     pip install tweepy, which is the python twitter client
 #
 # 2.  create a new app in your account at dev.twitter.com
 #     and then plug in your consumer and app keys below.
 #     Trim all whitespace at beginning/end of your keys.
 #
 # 3.  the twitter app needs to have permissions changed to
 #     read-write, as apps are read-only by default.
 # 
 # 4.  Execute this script: python unfollow.py

 import time
 import tweepy
 import sys

 auth = tweepy.auth.OAuthHandler(
        consumer_key='foo',
        consumer_secret='bar')
 auth.set_access_token(
        'foobaz',
        'foobar')

 api=tweepy.API(auth_handler=auth)

 print "Loading followers.."
 follower_objects = [follower for follower in tweepy.Cursor(api.followers).items()]

 print "Found %s followers, finding friends.." % len(followers)
 friend_objects = [friend for friend in tweepy.Cursor(api.friends).items()]

 # create dictionaries based on id's for easy lookup
 friends = dict([(friend.id, friend) for friend in friend_objects])
 followers = dict([(follower.id, follower) for follower in follower_objects])

 # find all your "non_friends" - people who don't follow you even though you follow them.
 non_friends = [friend for friend in friend_objects if friend.id not in followers]

 # double check, since this could be a rather traumatic operation.
 print "Unfollowing %s non-following users.." % len(non_friends)
 print "This will take approximately %s minutes." % (len(non_friends)/60.0)
 answer = raw_input("Are you sure? [Y/n]").lower()
 if answer and answer[0] != "y":
    sys.exit(1)

 # start the removal process. In the event of a failure (thanks, twitter!),
 # retry once after five seconds. An error on same record again is
 # probably more serious issue, so abort with error

 for nf in non_friends:
    print "Unfollowing " + str(nf.id).rjust(10)
    try:
        nf.unfollow()
    except:
        print "  .. failed, sleeping for 5 seconds and then trying again."
        time.sleep(5)
        nf.unfollow()
    print " .. completed, sleeping for 1 second."
    time.sleep(1)
	#! /usr/bin/env python

	# how to unfollow everyone who isn't following you
	# By Jamieson Becker (Public Domain/no copyright, do what you will)

	# Easy instructions, even if you don't know Python
	#
	# 1. Install pip (apt-get install python-pip) and then
	# pip install tweepy, which is the python twitter client
	#
	# 2. create a new app in your account at dev.twitter.com
	# and then plug in your consumer and app keys below.
	# Trim all whitespace at beginning/end of your keys.
	#
	# 3. the twitter app needs to have permissions changed to
	# read-write, as apps are read-only by default.
	#
	# 4. Execute this script: python unfollow.py

	import time
	import tweepy
	import sys

	auth = tweepy.auth.OAuthHandler(
	consumer_key='foo',
	consumer_secret='bar')
	auth.set_access_token(
	'foobaz',
	'foobar')

	api=tweepy.API(auth_handler=auth)

	print "Loading followers.."
	follower_objects = [follower for follower in tweepy.Cursor(api.followers).items()]

	print "Found %s followers, finding friends.." % len(followers)
	friend_objects = [friend for friend in tweepy.Cursor(api.friends).items()]

	# create dictionaries based on id's for easy lookup
	friends = dict([(friend.id, friend) for friend in friend_objects])
	followers = dict([(follower.id, follower) for follower in follower_objects])

	# find all your "non_friends" - people who don't follow you even though you follow them.
	non_friends = [friend for friend in friend_objects if friend.id not in followers]

	# double check, since this could be a rather traumatic operation.
	print "Unfollowing %s non-following users.." % len(non_friends)
	print "This will take approximately %s minutes." % (len(non_friends)/60.0)
	answer = raw_input("Are you sure? [Y/n]").lower()
	if answer and answer[0] != "y":
	sys.exit(1)

	# start the removal process. In the event of a failure (thanks, twitter!),
	# retry once after five seconds. An error on same record again is
	# probably more serious issue, so abort with error

	for nf in non_friends:
	print "Unfollowing " + str(nf.id).rjust(10)
	try:
	nf.unfollow()
	except:
	print " .. failed, sleeping for 5 seconds and then trying again."
	time.sleep(5)
	nf.unfollow()
	print " .. completed, sleeping for 1 second."
	time.sleep(1)