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@petergi
Created April 8, 2026 15:28
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// Finds the index of a given element in a sorted array using the binary search algorithm.
//
// - Declare the left and right search boundaries, `l` and `r`, initialized to `0` and the `length` of the array respectively.
// - Use a `while` loop to repeatedly narrow down the search subarray, using `Math.floor()` to cut it in half.
// - Return the index of the element if found, otherwise return `-1`.
// - **Note:** Does not account for duplicate values in the array.
const binarySearch = (arr, item) => {
let l = 0,
r = arr.length - 1;
while (l <= r) {
const mid = Math.floor((l + r) / 2);
const guess = arr[mid];
if (guess === item) return mid;
if (guess > item) r = mid - 1;
else l = mid + 1;
}
return -1;
};
binarySearch([1, 2, 3, 4, 5], 1); // 0
binarySearch([1, 2, 3, 4, 5], 5); // 4
binarySearch([1, 2, 3, 4, 5], 6); // -1
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