Created
June 5, 2018 04:12
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Check if a string IP address is in a CIDR range in SQL Server
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create function dbo.IPAddressIsInRange(@ip as varchar(15), @range as varchar(18)) | |
returns bit | |
as | |
begin | |
declare @prefix varchar(15), | |
@cidr varchar(2), | |
@mask bigint | |
set @prefix = left(@range, charindex('/', @range) - 1) | |
set @cidr = right(@range, len(@range) - charindex('/', @range)) | |
-- Converts to a bit mask, e.g. /24 = 255.255.255.0 | |
set @mask = 4294967295 - power(2, 32 - @cidr) + 1 | |
if (dbo.IPAddressToInteger(@ip) & @mask) = dbo.IPAddressToInteger(@prefix) | |
return 1 | |
return 0 | |
end | |
go |
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-- Credit: http://sqlblog.com/blogs/denis_gobo/archive/2008/10/05/9266.aspx | |
create function dbo.IPAddressToInteger(@ip as varchar(15)) | |
returns bigint | |
as | |
begin | |
return ( | |
convert(bigint, parsename(@ip, 1)) + | |
convert(bigint, parsename(@ip, 2)) * 256 + | |
convert(bigint, parsename(@ip, 3)) * 65536 + | |
convert(bigint, parsename(@ip, 4)) * 16777216 | |
) | |
end | |
go | |
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