sort a list by 2 key

example.md

sort.py

from itertools import groupby
from operator import itemgetter

def order_by(data, key1, key2, reverse_key1=False, reverse_key2=False):
    key1 = itemgetter(key1)
    key2 = itemgetter(key2)

    data = sorted(data, key=key1, reverse=reverse_key1)
    groups = groupby(data, key=key1)
    result = []
    for _, group in groups:
        result.extend(sorted(group, key=key2, reverse=reverse_key2))
    return result


if __name__ == "__main__":
    result = order_by([
        {
            "key1": 1,
            "key2": 2
        },
        {
            "key1": 2,
            "key2": 2
        },
        {
            "key1": 1,
            "key2": 3
        },
        {
            "key1": 2,
            "key2": 1
        }
    ], "key1", "key2", reverse_key1=False, reverse_key2=True)
    print(result)