Skip to content

Instantly share code, notes, and snippets.

@pinalbhatt
Last active January 4, 2016 13:59
Show Gist options
  • Save pinalbhatt/8631102 to your computer and use it in GitHub Desktop.
Save pinalbhatt/8631102 to your computer and use it in GitHub Desktop.
/*
Javascript
ResolveReferences - To resolve references in JSON object with circular references.
*/
function ResolveReferences(json) {
if (typeof json === 'string')
json = JSON.parse(json);
var byid = {}, // all objects by id
refs = []; // references to objects that could not be resolved
json = (function recurse(obj, prop, parent) {
if (typeof obj !== 'object' || !obj) // a primitive value
return obj;
if (Object.prototype.toString.call(obj) === '[object Array]') {
for (var i = 0; i < obj.length; i++)
if ("$ref" in obj[i])
obj[i] = recurse(obj[i], i, obj);
else
obj[i] = recurse(obj[i], prop, obj);
return obj;
}
if ("$ref" in obj) { // a reference
var ref = obj.$ref;
if (ref in byid)
return byid[ref];
// else we have to make it lazy:
refs.push([parent, prop, ref]);
return;
} else if ("$id" in obj) {
var id = obj.$id;
delete obj.$id;
if ("$values" in obj) // an array
obj = obj.$values.map(recurse);
else // a plain object
for (var prop in obj)
obj[prop] = recurse(obj[prop], prop, obj);
byid[id] = obj;
}
return obj;
})(json); // run it!
for (var i = 0; i < refs.length; i++) { // resolve previously unknown references
var ref = refs[i];
ref[0][ref[1]] = byid[ref[2]];
// Notice that this throws if you put in a reference at top-level
}
return json;
}
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment