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@pixelsnob
Last active September 13, 2018 19:48
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Sort an array of strings and numbers, but keeping the position of where strings or numbers appear in the original array
const arr = [
'tree', 'zebra', 40, 'y', 5000, 8, 14, 'zzzzz', 1, 'a', 'bbbbb'
];
let numbers_pos = [];
let words_pos = [];
let words_slots = [], numbers_slots = [];
arr.forEach((val, i) => {
if (typeof val == 'string') {
words_pos[i] = val;
words_slots.push(i);
} else {
numbers_pos[i] = val;
numbers_slots.push(i);
}
});
let words = words_pos.filter(val => !!val).sort((a, b) => a.localeCompare(b));
let numbers = numbers_pos.filter(val => !!val).sort((a, b) => a > b ? 1 : (a == b ? 0 : -1));
let sorted = [];
words.forEach((word, i) => {
let slot = words_slots[i];
sorted[slot] = word;
});
numbers.forEach((number, i) => {
let slot = numbers_slots[i];
sorted[slot] = number;
});
console.log(arr, sorted);
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