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December 22, 2015 03:19
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My PHP solution to Project Euler problem # 1 http://projecteuler.net/problem=1 If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
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| <?php | |
| $sum = 0; | |
| for ($i = 0; $i < 1000; $i++) { | |
| if (!($i % 3) || !($i % 5)) { | |
| $sum += $i; | |
| } | |
| } | |
| echo $sum; | |
| ?> |
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code in revision 9a8e4d24c7a9df5cbd8f6b7794fd521f55269585 took 0.0017611980438232 seconds to finish.
whereas, code in revision de495615e1f9741a39e00bf4ee5cc88d6360c880 took only 0.00026798248291016 to finish.