Created
November 3, 2018 23:56
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Suppose we want to encode <toto, so : | |
< t o t o | |
60 116 111 116 111 // in decimal | |
00111100 01110100 01101111 01110100 01101111 // in binary | |
00111100 01110100 01101111 01110100 01101111 00000000 // add optionnal complement (00000000) to have a multiple of 24 bits | |
001111 000111 010001 101111 011101 000110 111100 000000 // group of 6 * 3 bits | |
P H R v d G 8 = // use of Base64 index (see below) | |
If we want to encode <toto> | |
< t o t o > | |
60 116 111 116 111 62 // in decimal | |
00111100 01110100 01101111 01110100 01101111 00111110 // in binary | |
001111 000111 010001 101111 011101 000110 111100 111110 // in groupe of 3 x 6 bits. There is no rest, so no complement to add | |
P H R v d G 8 + | |
Remark : the before last character is still a 8 because the character > is 00111110 in binary. So the first 2 bits are zeros and so it is still a 8 value. | |
-------- | |
Base64 index : | |
Valeur Codage Valeur Codage Valeur Codage Valeur Codage | |
0 000000 A 17 010001 R 34 100010 i 51 110011 z | |
1 000001 B 18 010010 S 35 100011 j 52 110100 0 | |
2 000010 C 19 010011 T 36 100100 k 53 110101 1 | |
3 000011 D 20 010100 U 37 100101 l 54 110110 2 | |
4 000100 E 21 010101 V 38 100110 m 55 110111 3 | |
5 000101 F 22 010110 W 39 100111 n 56 111000 4 | |
6 000110 G 23 010111 X 40 101000 o 57 111001 5 | |
7 000111 H 24 011000 Y 41 101001 p 58 111010 6 | |
8 001000 I 25 011001 Z 42 101010 q 59 111011 7 | |
9 001001 J 26 011010 a 43 101011 r 60 111100 8 | |
10 001010 K 27 011011 b 44 101100 s 61 111101 9 | |
11 001011 L 28 011100 c 45 101101 t 62 111110 + | |
12 001100 M 29 011101 d 46 101110 u 63 111111 / | |
13 001101 N 30 011110 e 47 101111 v | |
14 001110 O 31 011111 f 48 110000 w (complément) = | |
15 001111 P 32 100000 g 49 110001 x | |
16 010000 Q 33 100001 h 50 110010 y |
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