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POJ 1180
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#include <cstdio> | |
#include <vector> | |
#include <deque> | |
#include <utility> | |
#include <algorithm> | |
#include <functional> | |
using namespace std; | |
typedef long long int LLI; | |
typedef pair<LLI, LLI> Pair; // (a, b) := ax+b | |
deque<Pair> lines; | |
int n; | |
LLI s; | |
LLI sumt[10001]; | |
LLI sumf[10001]; | |
LLI dp[10001]; // dp[m] := the minimum cost when disposing of 1 ~ m | |
int main() { | |
scanf("%d", &n); | |
scanf("%lld", &s); | |
for (int i=1; i<=n; i++) { | |
LLI t, f; | |
scanf("%lld %lld", &t, &f); | |
sumt[i] = sumt[i-1] + t; | |
sumf[i] = sumf[i-1] + f; | |
} | |
lines.push_back(Pair(sumf[n], s*sumf[n])); | |
for (int i=1; i<=n; i++) { | |
LLI m1, a1; | |
LLI m2, a2; | |
LLI m3, a3; | |
while (lines.size() > 1) { | |
m1 = lines[0].first; | |
a1 = lines[0].second; | |
m2 = lines[1].first; | |
a2 = lines[1].second; | |
if (m1*sumt[i] + a1 >= m2*sumt[i] + a2) lines.pop_front(); | |
else break; | |
} | |
m1 = lines[0].first; | |
a1 = lines[0].second; | |
dp[i] = m1*sumt[i] + a1; | |
m3 = sumf[n]-sumf[i]; | |
a3 = dp[i] + (s-sumt[i])*(sumf[n]-sumf[i]); | |
while (lines.size() > 1) { | |
m1 = lines[lines.size()-2].first; | |
a1 = lines[lines.size()-2].second; | |
m2 = lines[lines.size()-1].first; | |
a2 = lines[lines.size()-1].second; | |
if ((m2-m1) * (a3-a2) >= (a2-a1) * (m3-m2)) lines.pop_back(); | |
else break; | |
} | |
lines.push_back(Pair(m3, a3)); | |
} | |
printf("%lld\n", dp[n]); | |
} |
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