Created
December 30, 2012 09:09
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lua判断两天是否连续
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| local t1 = os.time{year = 2012, month = 12, day = 19, hour = 0, sec = 0} | |
| local t2 = os.time{year = 2012, month = 12, day = 19, hour = 23, sec = 59} | |
| if (t1 - t2) <= 86400 and | |
| (os.date("%d", t1) ~= os.date("%d",t2)) then | |
| -- 判断是否有新手目标 | |
| print("called") | |
| end |
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