Created
December 7, 2014 00:41
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findNumberWithBsearch
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<?php | |
function bsearch($number, $arr, $low, $high) { | |
//Traditional Recursive | |
if ($low > $high) { | |
return -1; | |
} | |
$mid = floor(($low + $high)/2); | |
if ($arr[$mid] == $number) { | |
return $mid; //Returns the index, Could also just return true if you just want the number to be found | |
} elseif ($arr[$mid] > $number) { | |
return bsearch($number, $arr, $low, $mid - 1); | |
} elseif ($arr[$mid] < $number) { | |
return bsearch($number, $arr, $mid + 1, $high); | |
} | |
} | |
function findIndexOfLargestNumber($arr,$low,$high) { | |
//we need 500 before we can proceed with the normal binary search | |
if ($low == $high && $high == 0) return 0; | |
while($low < $high) { | |
$mid = $low + floor(($high - $low)/2); | |
if($mid==0 || ($mid == $high) || ($arr[$mid]>$arr[$mid+1])) return $mid; | |
else if($arr[$mid]>$arr[$low]) $low=$mid; | |
else $high = $mid; | |
} | |
} | |
$arr = array(8, 10, 20, 80, 100, 200, 400, 500, 3, 2, 1); | |
$number = 20; | |
$count = count($arr)-1; | |
$indexOfLargestNumber = findIndexOfLargestNumber($arr,0,$count); //Thinks it gonna be OnLogn | |
echo "Largest number index is $indexOfLargestNumber <br/>"; | |
if ($number <= $arr[$indexOfLargestNumber]) echo "Index of the number $number (-1 indicates not found) => " . bsearch($number,$arr,0,$indexOfLargestNumber); | |
else echo "Result (-1 indicates not found) => " . bsearch($number,$arr,$indexOfLargestNumber+1,$count); | |
?> |
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