Check if two strings are Anagram

check_anagram.py

# this problem can be solve using Hashmap with O(N) time

def check_anagram(s1, s2):
    if len(s1) != len(s2): # check for base case
        return False
    counter = [0]*26        # each character of string is between a-z
    n = ord("a")            # integer value of "a" that is 97
    for i in range(len(s1)):
        counter[ord(s1[i]) - n] += 1  # update counter at each character
        counter[ord(s2[i]) - n] -= 1  # decrease counter at each character
    
    for x in counter:    # check if characters are same or not
        if x != 0:
            return Flase

    return True   # if all characters are same
    
s1 = "hackyourcode"   # first string 
s2 = "codehackyour"   # second String

print(check_anagram(s1,s2))

# the output will be "True"