Four sum problem solution in Python (4sum)

4sum.py

def findFourElements(arr, N, K):
    arr.sort()
    for i in range(N - 3):
        if i > 0 and arr[i] == arr[i-1]:
            continue
        for j in range(i+1, N - 2):
            if j > i+1 and arr[j] == arr[j - 1]:
                continue
            l = j+1
            r = N - 1
            while(l < r):
                sm = arr[i] + arr[j] + arr[l] + arr[r]
                if sm == tar:
                    # here print all four elements
                    print(arr[i], arr[j], arr[l], arr[r])
                    while l < r and arr[l] == arr[l+1]:
                        l += 1
                    while l < r and arr[r] == arr[r-1]:
                        r -= 1
                    l += 1
                    r -= 1
                elif sm < tar:
                    l += 1
                else:
                    r -= 1


# here take required input 
N, K = [int(v) for v in input().split()]
arr = [int(v) for v in input().split()]
findFourElements(arr, N, K)