Four sum problem solution (4sum)

4sum.cpp

#include <iostream>
#include <bits/stdc++.h>
using namespace std;

int getSum(int arr[],int N, int K) {
    for(int i=0; i < N; i++){
        if(i > 0 && arr[i] == arr[i+1]) {
            continue;
        }
        for(int j=i+1; j<N; j++) {
            if(j > 0 && arr[j] == arr[j+1]) {
                continue;
            }
            int l = j+1;
            int r = N-1;
            while(l < r) {
                int sum = arr[i] + arr[j] + arr[l] + arr[r];
                if(sum == K) {
                    cout << arr[i] << " "<< arr[j] << " "<< arr[l] << " "<< arr[r] <<endl;
                    while(l < r && arr[l] == arr[l+1]) l++;
                    while(l < r && arr[r] == arr[r-1]) r--;
                    l+=1;
                    r-=1;
                } else if(sum > K) {
                    r-=1;
                } else {
                    l+=1;
                }
            }
        }
    }
return 0;
}

int main() {
    int N;
    cin >> N;
    int K;
    cin >> K;
    int arr[N];

    for(int i=0; i<N; i++) {
        cin >> arr[i];
    }

    sort(arr, arr + N);

    if(N < 4) {
        cout <<" "<<endl;
    } else {
        getSum(arr, N, K);
    }
    
    return 0;
}