Pandu Rendradjaja prendradjaja

IMO the right question is "Why do both type and interface exist?"

You already know why interface exists -- so you can define an object type by naming its properties e.g.

interface Point {
    x: number;
    y: number;
}

https://leetcode.com/problems/remove-element/description/

This was interesting: I made this problem a lot harder by trying to move the "to remove" elements to the end instead of moving the "to keep" elements to the beginning.

I found my idea hard to implement iteratively, and I had to switch to recursion to get it working. After that, I was able to convert my solution to iterative -- but it would've been pretty hard to implement this approach iteratively from the start!

See https://github.com/prendradjaja/advent-of-code-2024/blob/main/trace.py

Guards

main = do
  print $ mySignum (-2)
  print $ mySignum 0
  print $ mySignum 2

mySignum n
  | n < 0 = -1
 | n &gt; 0 = 1

https://npm.runkit.com/jscodeshift

	(;GM[1]FF[4]CA[UTF-8]AP[CGoban:3]ST[2]
	RU[Chinese]SZ[19]KM[7.50]TM[7200]OT[3x60 byo-yomi]
	PW[Lee Sedol]PB[AlphaGo]WR[9p]DT[2016-03-13]C[Game 4 - Endurance

	Commentary by Fan Hui 2p
	Expert Go analysis by Gu Li 9p and Zhou Ruiyang 9p
	Translated by Lucas Baker, Thomas Hubert, and Thore Graepel

	When I arrived in the playing room on the morning of the fourth game, everyone appeared more relaxed than before. Whatever happened today, the match had already been decided. Nonetheless, there were still two games to play, and a true professional like Lee must give his all each time he sits down at the board.

	km \| mi (est.) \| mi (act.) \| error
	-----------------------------------
	1 \| 1 \| 0.62 \| 60.9%
	2 \| 1 \| 1.24 \| -19.5%
	3 \| 2 \| 1.86 \| 7.3%
	5 \| 3 \| 3.11 \| -3.4%
	8 \| 5 \| 4.97 \| 0.6%
	13 \| 8 \| 8.08 \| -1.0%
	21 \| 13 \| 13.05 \| -0.4%
	34 \| 21 \| 21.13 \| -0.6%

	import re


	def sscanf(s, fmt):
	'''
	Parses the string against the given template, returning the values of the
	slots. If no match, return None.

	The string must be a full match (like re.fullmatch()).

	class Draggable {
	private element: HTMLElement;

	private currentDrag: undefined \| {
	initialMouseX: number,
	initialMouseY: number,
	initialElementX: number,
	initialElementY: number,
	removeListeners: () => void,
	};