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@primaryobjects
Created August 19, 2023 01:26
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const merge = (nums1, m, nums2, n) => {
let index = m + n - 1; // Pointer to the current index being written to.
let i = m - 1; // Pointer to value to compare in nums1.
let j = n - 1; // Pointer to value to compare in nums2.
// Move from right to left, compare values i, j and write larger at index.
// If no more vaues in nums2, just choose nums1.
while (index >= 0) {
nums1[index--] = j < 0 || nums1[i] > nums2[j] ? nums1[i--] : nums2[j--];
}
return nums1;
};
const merge = (nums1, m, nums2, n) => {
let i = m-1;
let j = n-1;
let index = m+n-1;
while (j >= 0) {
if (i >= 0 && nums1[i] > nums2[j]) {
nums1[index--] = nums1[i--];
}
else {
nums1[index--] = nums2[j--];
}
}
return nums1;
};
You are given two integer arrays nums1 and nums2, sorted in non-decreasing order, and two integers m and n, representing the number of elements in nums1 and nums2 respectively.
Merge nums1 and nums2 into a single array sorted in non-decreasing order.
The final sorted array should not be returned by the function, but instead be stored inside the array nums1. To accommodate this, nums1 has a length of m + n, where the first m elements denote the elements that should be merged, and the last n elements are set to 0 and should be ignored. nums2 has a length of n.
Example 1:
Input: nums1 = [1,2,3,0,0,0], m = 3, nums2 = [2,5,6], n = 3
Output: [1,2,2,3,5,6]
Explanation: The arrays we are merging are [1,2,3] and [2,5,6].
The result of the merge is [1,2,2,3,5,6] with the underlined elements coming from nums1.
Example 2:
Input: nums1 = [1], m = 1, nums2 = [], n = 0
Output: [1]
Explanation: The arrays we are merging are [1] and [].
The result of the merge is [1].
Example 3:
Input: nums1 = [0], m = 0, nums2 = [1], n = 1
Output: [1]
Explanation: The arrays we are merging are [] and [1].
The result of the merge is [1].
Note that because m = 0, there are no elements in nums1. The 0 is only there to ensure the merge result can fit in nums1.
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