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December 31, 2019 07:47
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Prime number generator.
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# Author: Pedja | |
print(" ***** PROTOS *****\n\n\n") | |
while True: | |
n=int(input("Enter the ordinal number : ")) | |
def lcm(p,q): | |
p, q = abs(p), abs(q) | |
m = p * q | |
if not m: return 0 | |
while True: | |
p %= q | |
if not p: return m // q | |
q %= p | |
if not q: return m // p | |
def nthprime(n): | |
b1=2 | |
b2=2 | |
x=2 | |
k=3 | |
m=2 | |
while m<=n: | |
b3=b1+lcm(k-1,b1) | |
a=b3/b1-1 | |
k=k+1 | |
b1=b2 | |
b2=b3 | |
if x<a: | |
x=a | |
m=m+1 | |
return int(x) | |
if n<1: | |
print("Number must be greater than zero") | |
elif n==1: | |
print("The nth prime is 2") | |
else: | |
print("The nth prime is "+str(nthprime(n))) | |
try_again = "" | |
# Loop until users opts to go again or quit | |
while not(try_again == "1") and not(try_again == "0"): | |
try_again = input("Press 1 to try again, 0 to exit. ") | |
if try_again in ["1", "0"]: | |
continue # a valid entry found | |
else: | |
print("Invalid input- Press 1 to try again, 0 to exit.") | |
# at this point, try_again must be "0" or "1" | |
if try_again == "0": | |
break | |
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