Group by the n spice

group_by_n.js

// Idea:
// get the main result set into:
// three seperate list in a main list: [[1,2,3], [1,2], [1,2....,n]]
// Maybe here in this case js will not clone the main list .
// it will manipulate the main list. Attention to it.

list = [1,2,3,4,5,6,7,8,9]

const group_by_n = (list) => {
  // same as before:
  let temp_list = []
  let group_base_spice = 3
  let group_base_spice_special_case_secon_row = 2
  let result_list = []

  for(item in list){
    if(item == 0 && list.length > group_base_spice){
      temp_list = list.splice(0, group_base_spice);
      result_list.push(temp_list);
      temp_list = [] // reset
      group_base_spice = group_base_spice_special_case_secon_row

    }
    if(item == 1 && list.length > group_base_spice){
      temp_list = list.splice(0, group_base_spice);
      result_list.push(temp_list);
      temp_list = []
      
    }
    // guess this line will throw error
    // before: result_list.append(list)
    // after: only add the rest of item
    result_list.push(list[item])
    
    console.log("this should show three seperate list:",result_list)
    return result_list;
  } 

}

One can loop thorough the lists subgroup and show view as specific class now

result should be = [[1,2,3], [4,5], [rest....n]]

now run a loop on the view file to get the sets as grouped.

like: while 1 -> 2 do this.

for row 3 just print rest or paginate .