Created
August 22, 2010 22:19
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| /* If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. | |
| The sum of these multiples is 23. | |
| Find the sum of all the multiples of 3 or 5 below 1000. | |
| */ | |
| // List comprehension | |
| object ex1_a { | |
| val multiples = for (i <- List.range(1, 1000) if i % 3 == 0 || i % 5 == 0 ) yield i; | |
| val answer = multiples.foldLeft (0) ((x,y) => x + y); | |
| } | |
| // Using sets | |
| object ex1_b { | |
| val multiplesOf3 = 0 until 1000 by 3 | |
| val multiplesOf5 = 0 until 1000 by 5 | |
| //val answer = (multiplesOf3 union multiplesOf5).foldLeft (0) ((x,y) => x + y); //Range union isn't set union | |
| //val answer = multiplesOf3.union(multiplesOf5).foldLeft (0) ((x,y) => x + y); | |
| val answer = new scala.collection.immutable.HashSet().++(multiplesOf3).++(multiplesOf5).foldLeft (0) ((x,y) => x + y); | |
| } | |
| // Lazy list | |
| object ex1_c { | |
| lazy val multiples = for (i <- Iterator.from(0) if i % 3 == 0 || i % 5 == 0 ) yield i; | |
| val answer = multiples.takeWhile((x) => x < 1000).foldLeft (0) ((x,y) => x + y); | |
| } |
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