Go sqrt example

tour-golang.go

// http://tour.golang.org/#45
// by Perry Stoll

package main
 
import (
        "fmt"
        "math"
)
 
func MySqrt(x float64) float64 {
        z:=1.0
        min_delta := 0.00000000001
        delta := 1.0
        i := 0
        for ; math.Abs(delta) > min_delta ; i++{
                delta = (z*z - x)/(2*z)
                //fmt.Println(z,delta)
                z = z - delta
        }
        fmt.Println("iterations: ", i)
        return z
}
 
 
func main() {
        val := 9987665555.0
        fmt.Println(MySqrt(val))
        fmt.Println(math.Sqrt(val))
}

Can this function go a precision of min_delta =10 ^ -1000