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Permutations And Combinations
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class Combinations { | |
/* | |
a b c | |
0 0 0 -> [] | |
0 0 1 -> [c] | |
0 1 0 -> [b] | |
... | |
1 1 0 -> [a b] | |
1 1 1 -> [a b c] | |
*/ | |
public List<List<Integer>> subsets(int[] nums) { | |
int n = 1 << nums.length; | |
List<List<Integer>> res = new ArrayList<>(); | |
for(int i=0;i<n;i++) { | |
List<Integer> tmp = new ArrayList<>(); | |
for(int bit=0;bit<nums.length;bit++) { | |
int probe = 1<<bit; | |
if((probe & i) != 0) { | |
tmp.add(nums[bit]); | |
} | |
} | |
res.add(tmp); | |
} | |
return res; | |
} | |
} |
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class Permutations { | |
public List<List<Integer>> permute(int[] nums) { | |
List<List<Integer>> res_list = new ArrayList<>(); | |
helper(nums, res_list, 0); | |
return res_list; | |
} | |
private void helper(int[] nums, List<List<Integer>> res_list, int curr) { | |
if(curr == nums.length) { | |
res_list.add(Arrays.stream(nums).boxed().collect(Collectors.toList())); | |
return; | |
} | |
for(int i=curr;i<nums.length;i++) { | |
// code from Jianzhi Offer | |
// swap curr to [curr,|arr|-1] | |
// e.g | |
// 1,2,3 2,1,3 3,2,1 | |
// 1,3,2 2,3,1 3,1,2 | |
{ | |
int tmp = nums[i]; | |
nums[i] = nums[curr]; | |
nums[curr] = tmp; | |
} | |
helper(nums, res_list, curr+1); | |
{ | |
int tmp = nums[i]; | |
nums[i] = nums[curr]; | |
nums[curr] = tmp; | |
} | |
} | |
} | |
} |
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// 无重复的全排列,例如abb的无重复全排列为 | |
// a b b | |
// b b a | |
// b a b | |
public class PermutationsWithoutRepeat { | |
static void helper(char[] arr, int curr) { | |
if (curr == arr.length) { | |
for (char anArr : arr) { | |
System.out.print(anArr + " "); | |
} | |
System.out.println(); | |
} | |
for (int i = curr; i < arr.length; i++) { | |
boolean swapable = true; | |
// i是要被交换的元素 | |
// 如果要被交换的元素i之后有和arr[i]相同的元素,则不继续交换 | |
// 例如 abb, 当curr=0, i=1时,因为arr[2]和arr[1]相同,则arr[0]不与arr[1]交换 | |
for (int j = i + 1; j < arr.length; j++) { | |
if (arr[i] == arr[j]) { | |
swapable = false; | |
break; | |
} | |
} | |
if (swapable) { | |
{ | |
char tmp = arr[curr]; | |
arr[curr] = arr[i]; | |
arr[i] = tmp; | |
} | |
helper(arr, curr + 1); | |
{ | |
char tmp = arr[curr]; | |
arr[curr] = arr[i]; | |
arr[i] = tmp; | |
} | |
} | |
} | |
} | |
public static void main(String[] args) { | |
char[] arr = "abb".toCharArray(); | |
helper(arr, 0); | |
} | |
} |
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