This is a simple program to calculate the last intelligible 70% of any string of text, also known as Wadsworth's Constant

wadsworth_constant.py

#! /bin/python
print "Wadsworth's Constant"
theString = raw_input('] ')
theStringLength = len(theString)
WadsworthsAmount = int(round((0.3) * theStringLength))
firstSpace = theString.find(' ', WadsworthsAmount)
if firstSpace == -1:
    FinalString = theString[WadsworthsAmount:]
else:
    FinalString = theString[firstSpace+1:]

print FinalString

from sys import argv
str = ' '.join(argv)
print str[str.find(' ', int(round(0.3 * len(str))))+1:]

Wow! Didn't think of that! Very clever.

(lambda s:(lambda r:s.stdout.write(r[r.find(' ', int(0.3 * len(r)))+1:]+'\n'))(' '.join(s.argv)))(__import__('sys'))

What about this one?

def wadsworth(s):
    return s[int(30*len(s)/100.+.5):]

@jabbalaci
That doesn't split the array on whitespace.

@aelse
No, but it chops off the first 30% of any text.