python tips

about_sorted.py

>>> engine_res
[1, 2, 3, 4, 6, 5, 7]
>>> db_res
[(4, 'no1'), (1, 'no1'), (7, 'no1'), (2, 'no1'), (5, 'no1'), (3, 'no1'), (6, 'no1')]
>>> sorted(db_res,key=lambda k:engine_res.index(k[0]))
[(1, 'no1'), (2, 'no1'), (3, 'no1'), (4, 'no1'), (6, 'no1'), (5, 'no1'), (7, 'no1')]

func_param_list.py

>>> def func(a,b,c):
...   print a,b,c
... 
>>> func(*[1,2,3])
1 2 3

numcard.py

print '10X98765432'[reduce(lambda x,y  +y, map(lambda x:int(x[0])*x[1], zip('51000018880101001'[0:17], [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2]) )) % 11]

'''
想生成一个合法的18位良民证用于注册防沉迷？不妨试试上面的one liner python script。其中51000018880101001前5位是地区，接下来是生日，最后三位随便弄，奇数男的偶数女的。最后一位由上面的python代码获得。有的漏洞还可以注册形如19880431这样的日期。呵呵。
'''

pyencode.py

s = "\u5317\u4eac"
s = eval("u'%s'" % s)
s.encode('gb18030') 

tab_complete.py

import rlcompleter, readline
readline.parse_and_bind('tab: complete')

unicode_and_utf8.py

# encodin : utf-8

def tostr(s):
    return "".join(map(lambda c:chr(ord(c)),s))

s = u'\xe4\xbd\xa0\xe5\xa5\xbd'
print tostr(s)