This 8086 assembly code checks even or odd and prints their output. The code is explained in comments line by line.

Even Odd Checker Explanation.asm

;Author:quickgrid
;Site:  http://quickgrid.blogspot.com
;Code:  Even odd check 8086 assembly code



;predefined macro for speed coding
;define any code here that is reduandant 
newline macro
         
  lea dx,nl
  mov ah,9
  int 21h
  
endm
  
  
  
.model small
.stack 100h



.data

;remermber to put a $ after or if you want it
;keep executing than put it on other line
msg1 db 'number is even', '$'
msg2 db 'number is odd',  '$'
nl   db  0dh,0ah,         '$'



.code 
.startup
  
  ;initialize data segment  
  mov ax,@data
  mov ds,ax
     
  
  ;ah=1 is take input, int 21h execute above command   
  mov ah,1
  int 21h
  

  ;divide al by whatever is in bl
  mov bl,2
  div bl
  
  ;ah contains remainder after division, al contains the operand, no need for
  ;operand anymore replace with remainder
  mov al,ah
  
  ;check if remainder is zero
  cmp al,0
  
  ;use any condition here jump greater, jump if not equal etc
  jg odd 
          
          
  
  ;if it was a odd number than it would never reach here
  ;print a new line if even
  even:
    newline  
  
  
  ;print the string in msg1 and skip rest of the code to exit label
  lea dx,msg1
  mov ah,9
  int 21h
  jmp exit 
  
  
    
  ;the previous jg odd label jumps to here skipping even portion of the code    
  odd:
    newline        
          
            
  ;show the message for odd number        
  lea dx,msg2
  mov ah,9
  int 21h
          
  
  ;just a jump label to skip executing some codes        
  exit:
  
 
.exit

Thanks for giving this.