Sums of consecutive integers

sums_consecutive_position.js

/**
 * Given the number of consecutive integers and the total of the integers,
 * return the consecutive integer at the requested position.
 *
 * @param {int} x number of consecutive integers
 * @param {int} y sum of consecutive integers
 * @param {int} n position of requested integer
 * @return {int} consecutive integer at requested position
 */
function position(x, y, n) {
  let numList = [];
  
  for(let a = 0; a < x; a++) numList.push(a);
   
  let currentSum = getSum(numList); 
  
  if (currentSum === y) return numList[n];
  
  let remainder = Math.floor((y - currentSum) / x);
  return numList.map((el) => el + remainder))[n];
}

function getSum(array) {
  return array.reduce((prev, current) => prev + current);
};