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// http://www.geeksforgeeks.org/find-last-digit-of-ab-for-large-numbers/ | |
//http://qa.geeksforgeeks.org/1061/given-big-number-form-string-how-do-take-mod-of-that-big-number | |
var asciiZero = "0".charCodeAt(0); | |
var findModulo = function(base, exponent) { | |
var mod = 0; | |
for (var i in exponent) { | |
//mod = (mod*10 + b[i] - '0')%a; | |
mod = (mod * 10 + exponent.charCodeAt(i) - asciiZero) % base; | |
} | |
return mod; | |
} | |
var lastDigit = function(str1, str2){ | |
if (str1.length === 1 && str2.length === 1 && str1 === "0" && str2 === "0") { | |
return 0; | |
} | |
if (str2.length === 1 && str2 === "0") { | |
return 1; | |
} | |
if (str1.length === 1 && str1 === "0") { | |
return 0; | |
} | |
var e = findModulo(4, str2); | |
if (e === 0) { | |
e = 4; | |
} | |
var res = Math.pow(str1[str1.length - 1].charCodeAt(0) - asciiZero, e); | |
// Return last digit of result | |
return res % 10; | |
} |
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