Created
August 17, 2018 12:46
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Generate n-bit gray codes. Given a number n, generate bit patterns from 0 to 2^n-1 such that successive patterns differ by one bit.
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import java.io.*; | |
import java.lang.*; | |
import java.util.*; | |
class nBitGrayCode { | |
public static void main(String[] args) { | |
int n = 3; | |
ArrayList<StringBuilder> list = new ArrayList<>(); | |
list.add(new StringBuilder("0")); | |
list.add(new StringBuilder("1")); | |
ArrayList<StringBuilder> list1 = new ArrayList<>(); | |
ArrayList<StringBuilder> list2 = new ArrayList<>(); | |
for (StringBuilder s : list) { | |
list1.add(new StringBuilder(s)); | |
list2.add(new StringBuilder(s)); | |
} | |
for (int i = 0; i < n-1; i++) { | |
for (StringBuilder a : list1) | |
a.insert(0, "0"); | |
// System.out.println(list1); | |
for (StringBuilder b : list2) | |
b.insert(0, "1"); | |
// System.out.println(list2); | |
list.clear(); | |
list.addAll(list1); | |
list.addAll(list2); | |
list1.clear(); | |
for (StringBuilder s : list) { | |
list1.add(new StringBuilder(s)); | |
} | |
list2.clear(); | |
for (StringBuilder s : list) { | |
list2.add(new StringBuilder(s)); | |
} | |
System.out.println(list + "\n"); | |
} | |
} | |
} |
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