Created
March 9, 2015 08:54
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Dynamic programming for palindrome finder
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__author__ = 'rakesh' | |
# print out the highest palindrome and length of each palindrome exist in the string | |
def Palindrome(text): | |
list = [] | |
palindrome = [] | |
new_list = [] | |
f = [] | |
for k in range(0, len(text)): | |
list.append(text[k]) | |
j = len(text) - 1 | |
i = 0 | |
print i, j | |
def LP(i, j): | |
if j == 0: | |
return 1 | |
elif i == j: | |
return 1 | |
elif j == (i + 1) and text[i] != text[j]: | |
return 1 | |
elif j == (i + 1) and text[i] == text[j]: | |
return 2 | |
elif text[i] == text[j]: | |
palindrome.append(list[i:j+1]) | |
return LP(i+1, j-1) + 2 | |
else: | |
return max(LP(i+1, j), LP(i, j-1)) | |
print LP(i, j) | |
for i in range(0, len(palindrome)): | |
new_list.append("".join(palindrome[i])) | |
for line in new_list: | |
if Palindrome_print(line) == 1: | |
f.append(line) | |
for line in set(f): | |
print line, len(line) | |
def Palindrome_print(string): | |
x = len(string) | |
count = 1 | |
for i in range(0, x/2): | |
if string[i] != string[x-1]: | |
count = 0 | |
x = x -1 | |
return count | |
Palindrome("pagap") | |
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