CakePHP: Render view in a variable inside controlller

render_view_as_variable.php

<?php

$view = new View($this, false);
$view->set(compact('some', 'vars'));
$html = $view->render('view_name');

Thank you.

Thanks! Works with "cakephp/cakephp": "2.6.*". I'd add, that to render without the layout, just set $view->layout = null, or at least that's what worked for me.

This still works in 3.0.*, with slightly tweaked code:

$view = new View($this->request);
$view->set(compact('some', 'vars'));
$html = $view->render('view_name');

Very helpful, thank you!

public function index()
{
$this->set(compact('users'));
$this->set('_serialize', ['users']);

}

i am not able to call simple view from my controller ..pls help.

Thanks!!

what if the View is for a different Controller?

Thank u very much! Work like a charm! (also i created empty.ctp Layout, but how suggest @TamasBarta it can be disabled)

For different controller view just pass the path of the .ctp file in the render() method call...

$view = new View($your_controller || $this, false);

$view->layout = false; //if you donot want to render it in template

$view->set('some_data', $some_data);

$html = $view->render('../back/path/to/the/other/controller/ctp/file.ctp');

	public function template(){
		
		$entity = TableRegistry::get('MyTable')->find()->last();
		
		$view = new View($this->request);
		$view->layout = false;
		$view->set(compact('entity'));
		$html = $view->render('Etiqueta'.DS.'por_aviso');
		
		debug($html);
		
	}