Created
November 10, 2018 18:05
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close all; | |
clear all; | |
load('noisy_ECG_sig.mat') | |
y=noisy_ECG_sig; %the signal loaded | |
L=length(y) | |
sampling_freq = 1000 | |
figure; % plot the original signal | |
plot([1:2570],y); | |
title('Original ECG Signal') | |
% Question 2) plot the frequency response of both the original signal(noisy_ECG_sig) and the filtered signal Yn | |
%% plot frequency response of the original signal %% | |
NFFT=2^nextpow2(L); | |
f = sampling_freq/2*linspace(0,1,NFFT/2+1); | |
Y=fft(y,NFFT)/L; | |
figure, plot(f,2*abs(Y(1:NFFT/2+1))); | |
title('frequency response of the original signal'); | |
ylabel('amplitude'); | |
xlabel('frequency'); | |
%% %% | |
num=[0.9955 -1.8936 0.9955]; | |
den=[1 -1.8936 0.9911]; | |
filtered_y = filter(num,den,y); | |
%% plot frequency response of the filtered signal %% | |
NFFT=2^nextpow2(L); | |
f = sampling_freq/2*linspace(0,1,NFFT/2+1); | |
f_Y=fft(filtered_y,NFFT)/L; | |
figure, plot(f,2*abs(f_Y(1:NFFT/2+1))); | |
title('frequency response of the filtered signal'); | |
ylabel('amplitude'); | |
xlabel('frequency'); | |
%% %% | |
figure; | |
plot([1:2570],filtered_y); % plot the filtered signal | |
title('Filtered ECG Signal') | |
% Question 3) By observing the distinct changes in the frequency components | |
% in the above frequency plots, predict the nature of the filter | |
fvtool(num,den) | |
%q4) verify your results using 'fvtool' matlab function |
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Hey, apologies for the broken link.
I uploaded it now, https://blog.ramith.fyi/static/math_embed/noisy_ECG_sig.mat