Notepad++ Advanced search and replace. Null, Enter char, Tab, Regular Expressions, Etc.

Notepad++AdvancedSearch.txt

Open the find/replace dialog.
At the bottom will be some Search mode options.  Select "Extended (\n \r \t \0 \x...)"
In either the Find what or the Replace with field entries, you can use the following escapes:
\n  new line (LF)
\r   carriage return (CR)
\t   tab character
\0  null character
\xddd   special character with code ddd

Notepad++RegularExpressions.txt

- [!] finds the exclamation character.

- .* selects the rest of the line.

- (\+.*)(Item) \+ finds the + character. | .* selects the text after the + up until the word "Item" | Item finds the string "Item" | () allow us to access whatever is inside the parentheses. The first set of parentheses may be accessed with \1 and the second set with \2.

- \1\r\n\2 will take + and whatever text comes after it, will then add a new line, and place the string "Item" on the new line.

- A-Z finds all letters of the alphabet in upper case.

- a-z finds all lower case letters.

- A-Za-z will find all alphabetic characters.

- [^...] is the inverse. So, if we put these three together: [^A-Za-z] finds any character except an alphabetic character.

- Notice that only one of the [^A-Za-z] is in parentheses (). This is recalled by \1 in the Replace with field. The characters outside of the parentheses are discarded.

How can I search for "VCP Address" then include all the number thereafter and stop the search on the last semicolon with no content? Also this would be multiple files.
; VCP Address : 1.2, 1.5, 1.7, 1,9
; 6.215, 5585.5, 4.2
; 3.14, 5.6, 2.5, 8.5
;

Hi

How would I find all numbers of the form

spacen:n where nn can be any number, single or multi digit, e.g. 2:14 or 23:9, or whatever?

thanks
TW.

Hi

How would I find all numbers of the form

spacen:n where nn can be any number, single or multi digit, e.g. 2:14 or 23:9, or whatever?

thanks
TW.

I know this is quite old, but for people with a similar problem, maybe something like this:
([0-9])[^:]
([0-9]) is the group for all numbers, and [^:] breaks that group if there's a colon (poorly explained due to the lack of my english knowledge)

Is there a way to identify a file if something is NOT present?
For example, show files that do not have any instances of "PEAR" "APPLE" "BANANA"
i.e show all files that do not have any of these

Hi
i want how to remove 1,2,5,6,9,10........ & 3,4,7,8,11,12........ line in notepad++.
Is there a way to delete line in that order?

I am hoping you can help me. I have a txt file with about 2000 characters. I want to find a word on char 123 but change the information in char 1662. I have tried to use the in selection but it does not work.
This is what I have: FIND WHAT: ^.{123}\K05
REPLACE WITH: [-c1662]2FIRST COMMONWEALTH BANK

It finds the character no problem but does not replace anything

I want to remove " 2567 " in "(2567, 510,........... )" including space after numbers(without quotes) and wants the output: (510,.....)
what will be regex in Find What: ??
and what is to be write in Replace With: ??

Expert advice needed please : I would like to remove the last column from | symbol on wards in below. Pl help.
A | 123|101|Roast
B | 137|201|Flower
C | 117|abcd|Just
D | 367|effg|Apple1

Data needed like below
A | 123|101
B | 137|201
C | 117|abcd
D | 367|effg

is it possible to increment number components in a selection? for example i have

"number": 1,
etc..
"number": 2,
etc..
"number":3

then i want to find "number:" and add 1 to the numbers following it so that i get
"number": 2,
etc..
"number": 3,
etc..
"number":4

How do we search for [a-z]$[a-z] $ preceded and succeeded by a lower case char

When I press the Enter key while editing an indented line, the cursor begins the next line aligned with the indentation of the previous line. When I use '\n' or '\r' in a search/replace operation, it does not align to the indentation of the previous line. Am I doing something wrong? It seems to me that '\r' should act just like the Enter key, no?

how to remove the last ";" from each line using replace

Hi i use np ++ for translating game, example i need find word Settings , how i can find word Settings anywhere without name="Settings" and string="Settings" ? Thx for Help, and sorry for my Bad English.

How i can replace Word in multiple Directories ? Be like C:\Program Files\Client1* C:\Program Files\Client2*

When I press the Enter key while editing an indented line, the cursor begins the next line aligned with the indentation of the previous line. When I use '\n' or '\r' in a search/replace operation, it does not align to the indentation of the previous line. Am I doing something wrong? It seems to me that '\r' should act just like the Enter key, no?

I realize this is old, but for anyone's future reference, the issue is that while Notepad++ automatically inserts previous indentation when inputting new lines, the search/replace function isn't aware of this. You need to include the necessary indentation in your search/replace.

The easiest way is merely drag-selecting the beginning part of that line (the empty indentation spacing) and then press CTRL-H to open "Replace" dialog. It will be pre-filled with the necessary search to locate that pattern of indentation. And then you can prepend a "\n" to the start of it to only search for new lines that start with that level of indentation.

Depending how your NP++ is set up to manage indentation - i.e. a tab vs. spaces - you may be able to utilize extended-search's "\t", which indicates a "tab".

For reference, an "Enter" for a newline (as it seems you're asking) equates to "\r\n", which is a carriage return + line-feed/newline operation, which is what the "CR LF" symbols are referencing at the end of each line, if you were to enable "Show symbols". This is a throwback reference to the days of the typewriter, where the "Enter" button equivalent merely dropped the cursor down one line, but wouldn't automatically bring it to the leftmost start of the line by default.

how to remove the last ";" from each line using replace

Enable the "Extended" search selector, and then in the "Find" box, add an "\r\n" to the right of your semicolon, e.g. ";\r\n". That will find only semicolons that are at the end of lines.

Note that if you are doing a "Replace" operation, you'll also need to add the "\r\n" to the end of the replace-text, otherwise the newline's will be removed, making it one long continuous line.