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Byte Pair Encoding example (Source: Sennrich et al.)
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import re, collections | |
def get_stats(vocab): | |
pairs = collections.defaultdict(int) | |
for word, freq in vocab.items(): | |
symbols = word.split() | |
for i in range(len(symbols)-1): | |
pairs[symbols[i],symbols[i+1]] += freq | |
return pairs | |
def merge_vocab(pair, v_in): | |
v_out = {} | |
bigram = re.escape(' '.join(pair)) | |
p = re.compile(r'(?<!\S)' + bigram + r'(?!\S)') | |
for word in v_in: | |
w_out = p.sub(''.join(pair), word) | |
v_out[w_out] = v_in[word] | |
return v_out | |
vocab = {'l o w </w>' : 5, 'l o w e r </w>' : 2, 'n e w e s t </w>':6, 'w i d e s t </w>':3} | |
num_merges = 6 | |
for i in range(num_merges): | |
pairs = get_stats(vocab) | |
best = max(pairs, key=pairs.get) | |
vocab = merge_vocab(best, vocab) | |
print(best) |
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