Created
May 2, 2017 07:00
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/* | |
Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be: | |
1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ... | |
By considering the terms in the Fibonacci sequence whose values do not exceed four million, find the sum of the even-valued terms. | |
*** PROBLEM WITH EULER CONDITION THEY SAY 4 MILLION BUT ACTUALLY MEAN 40 MILLION | |
*/ | |
fn fibonacci(limit : i32) -> Vec<i32> { | |
let mut i = 1; | |
let mut j = 2; | |
let mut fibs = vec![1,2]; | |
println!("{}",limit); | |
loop{ | |
let next_fib = i+j; | |
if next_fib > limit { | |
break; | |
} | |
fibs.push(next_fib); | |
i = j; | |
j = next_fib; | |
} | |
fibs | |
} | |
fn sum_even_fibs(v : Vec<i32> ) -> i32 { | |
let mut sum = 0; | |
for i in v { | |
if i % 2 == 0 { | |
sum += i; | |
} | |
} | |
sum | |
} | |
fn main(){ | |
let fib = fibonacci(4000000); | |
println!("{:?}",fib); | |
let sum = sum_even_fibs(fib); | |
println!("{}",sum); | |
} |
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