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Solutions for HackerRank Interview
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// derived this formula for summation of odd integers | |
def calculate(arr: Array[Int]) = { | |
arr.map{ | |
(days) => | |
val numOddPairs = Math.round((days - 1).toDouble / 4) | |
val numOddNumbers = Math.ceil(days.toDouble / 2).toInt | |
val midPoint = days match { | |
case _ => if (numOddNumbers % 2 == 1) Math.ceil(days.toDouble / 2).toInt else 0 | |
} | |
2 * Math.round((days + 1) / 2) * numOddPairs + midPoint | |
} | |
} | |
calculate((1 to 10).toArray) | |
//res0: Array[Long] = Array(1, 1, 4, 4, 9, 9, 16, 16, 25, 25) | |
def customSort(arr: Array[Int]) = { | |
arr.groupBy(identity).mapValues(_.length).toList.sortBy(x => x._2 -> x._1).flatMap { | |
case (num, freq) => List.fill(freq)(num) | |
} | |
} | |
customSort(Array(3, 1, 2, 2, 4)) | |
// res2: List[Int] = List(1, 3, 4, 2, 2) | |
def calculate_amount(arr: Array[Int]) : Long = { | |
def costFn(cost: Long, discount: Long) : Long = if (discount > cost) 0 else cost - discount | |
if (arr.length == 0) 0 else | |
arr.foldLeft((Long.MaxValue, 0.toLong)){ | |
case ((currMin, total), elem) => (Math.min(currMin, elem), | |
total.toLong + costFn(elem.toLong, Math.min(elem, currMin))) | |
}._2 + arr.head.toLong | |
} | |
calculate_amount(Array(4, 9, 2, 3)) | |
calculate_amount(Array(1, 2, 3, 4)) | |
//res5: Long = 10 | |
//res6: Long = 7 | |
def kSub(k: Int, nums: Array[Int]): Long = { | |
nums.scanLeft(0)(_ + _).map(_ % k).groupBy(identity).mapValues(_.length).values.map(x => x * (x - 1) / 2).sum | |
} | |
kSub(3, Array(1, 2, 3, 4, 1)) | |
kSub(2, Array(1, 2, 1, 2, 1, 2)) |
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