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Python Upload File to S3 Bucket
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| def upload_to_s3(event, context): | |
| body=str(event['body']) | |
| #"""Assuming Following Body | |
| #'------WebKitFormBoundarylaaNaialEQTotwSB\r\nContent-Disposition: form-data; name="file"; filename="test---.html"\r\nContent-Type: text/html\r\n\r\n<html>\n</html>\r\n------WebKitFormBoundarylaaNaialEQTotwSB--\r\n' | |
| #""" | |
| file_name = body.split(';')[2].split("\r\n")[0].split("=")[1].strip("\"") | |
| c_type, c_data = parse_header(event['headers']['content-type']) | |
| c_data['boundary'] = bytes(c_data['boundary'], "utf-8") | |
| body_file = BytesIO(bytes(event['body'], "utf-8")) | |
| form_data = parse_multipart(body_file, c_data) | |
| s3 = boto3.resource('s3') | |
| object = s3.Object(u'sl-html-demo',file_name) | |
| object.put(Body=form_data['file'][0]) | |
| response = str(get_page(str(event), 'upload_response', '')).format("<b>File Uploaded : </b>" + file_name) | |
| return return_html(response, str(event)) |
Author
ravishtiwari
commented
Mar 25, 2019
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