Gulp pipe function

gulpfile.js

'use strict';

var gulp = require('gulp');
var through = require('through2');

// https://gulp.readme.io/docs
gulp.task('default', () => {
  gulp.src('src/**/*')
      .pipe(pipeFunction())
      .pipe(gulp.dest('dist'))
});

var pipeFunction = () => {
  return through.obj((file, enc, cb) => {
    console.log(file.path);
    return cb(null, file);
  });
}

Thank you!!

isn't there a way to access the arguments in pipeFunction without using the through lib?