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@rcmachado
Created November 25, 2009 10:19
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$.unserialize for jQuery
/**
* $.unserialize
*
* Takes a string in format "param1=value1&param2=value2" and returns an object { param1: 'value1', param2: 'value2' }. If the "param1" ends with "[]" the param is treated as an array.
*
* Example:
*
* Input: param1=value1&param2=value2
* Return: { param1 : value1, param2: value2 }
*
* Input: param1[]=value1&param1[]=value2
* Return: { param1: [ value1, value2 ] }
*
* @todo Support params like "param1[name]=value1" (should return { param1: { name: value1 } })
*/
(function($){
$.unserialize = function(serializedString){
var str = decodeURI(serializedString);
var pairs = str.split('&');
var obj = {}, p, idx, val;
for (var i=0, n=pairs.length; i < n; i++) {
p = pairs[i].split('=');
idx = p[0];
if (idx.indexOf("[]") == (idx.length - 2)) {
// Eh um vetor
var ind = idx.substring(0, idx.length-2)
if (obj[ind] === undefined) {
obj[ind] = [];
}
obj[ind].push(p[1]);
}
else {
obj[idx] = p[1];
}
}
return obj;
};
})(jQuery);
@CyberShadow
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I don't understand how one implies the other.

$.get('page.php', $.unserialize('foo=bar%3Dbaz'));

This will create a request with a URL like page.php?foo=bar%253Dbaz. Special characters will be encoded twice.

@Komalbandi
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Nice.

@er1z
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er1z commented Aug 27, 2013

Think should be faster:

if (idx.constructor==[].constructor)

instead of

if (idx.indexOf("[]") == (idx.length - 2)) {

@brucekirkpatrick
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There are 2 bugs in this one, which I forked to fix: https://gist.github.com/brucekirkpatrick/7026682
Bug 1: the values were not unescaped. Bug 2: If you had 2 field names with the same name that didn't use the bracket naming convention, the extra values would be lost, they should become an array or at least a comma separated string. I choose array. Here is code to demonstrate the problems:
console.log($.unserialize("one="+escape("& = ?")+"&two="+escape("value1")+"&two="+escape("value2")+"&three[]="+escape("value1")+"&three[]="+escape("value2")+"&three[]="+escape("value3")));

@luislobo14rap
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