Last active
August 30, 2021 18:08
-
-
Save redswallow/7205365 to your computer and use it in GitHub Desktop.
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
C++ code snippets |
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
#include <iostream> | |
using namespace std; | |
void heapify(int a[], int i, int n){ | |
int l = 2*i+1; | |
int r = 2*i+2; | |
int largest = i; | |
if (l < n && a[l] > a[i]) largest = l; | |
if (r < n && a[r] > a[l]) largest = r; | |
if (largest != i){ | |
int tmp = a[i]; a[i] = a[largest]; a[largest] = tmp; | |
heapify(a, largest, n); | |
} | |
} | |
void heapsort(int a[], int n){ | |
for (int i = n/2-1; i>=0; i--) heapify(a, i, n); | |
for (int i = n-1; i>0; i--){ | |
int tmp = a[0]; a[0] = a[i]; a[i] = tmp; | |
heapify(a, 0, i); | |
} | |
} | |
int main(int argc, char const *argv[]) | |
{ | |
int a[5]={6, 7, 12,10,9}; | |
heapsort(a, 5); | |
for (int i=0;i<5;i++) | |
{ | |
cout << a[i] << " "; | |
} | |
return 0; | |
} |
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
// insertion_sort O(n^2) | |
insertion_sort(int s[],n) | |
{ | |
int i,j,min; | |
for (i=0;i<n-1;i++) | |
for (j=i+1;j<n;j++) | |
if (s[j]<s[min]) | |
swap(&s[i],&s[j]); | |
} |
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
// 1) Do In-Order Traversal of the given tree and store the result in a temp array. | |
// 3) Check if the temp array is sorted in ascending order, if it is, then the tree is BST. | |
// Time Complexity: O(n) | |
// http://www.geeksforgeeks.org/a-program-to-check-if-a-binary-tree-is-bst-or-not/ | |
bool isBST(struct node* root) | |
{ | |
static struct node *prev = NULL; | |
// traverse the tree in inorder fashion and keep track of prev node | |
if (root) | |
{ | |
if (!isBST(root->left)) | |
return false; | |
// Allows only distinct valued nodes | |
if (prev != NULL && root->data <= prev->data) | |
return false; | |
prev = root; | |
return isBST(root->right); | |
} | |
return true; | |
} |
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
#include <iostream> | |
using namespace std; | |
void merge(int a[], int temp[], int left, int mid, int right){ | |
int i = left, j = mid, k = left; | |
while (i <= mid - 1 && j <= right){ | |
if (a[i] <= a[j]){ | |
temp[k++] = a[i++]; | |
}else{ | |
temp[k++] = a[j++]; | |
} | |
} | |
while (i <= mid - 1) temp[k++] = a[i++]; | |
while (j <= right) temp[k++] = a[j++]; | |
for (i = left; i <= right; i++) a[i] = temp[i]; | |
} | |
void mergesort(int a[], int temp[], int left, int right){ | |
int mid = left + (right - left)/2; | |
if (right > left){ | |
mergesort(a, temp, left, mid); | |
mergesort(a, temp, mid+1, right); | |
merge(a, temp, left, mid+1, right); | |
} | |
} | |
void mergesort(int a[], int n){ | |
int *temp = (int *)malloc(sizeof(int)*n); | |
mergesort(a, temp, 0, n - 1); | |
free(temp); | |
} | |
int main(int argc, char const *argv[]) | |
{ | |
int a[5]={6, 7, 12,10,9}; | |
mergesort(a, 5); | |
for (int i=0;i<5;i++) | |
{ | |
cout << a[i] << " "; | |
} | |
return 0; | |
} |
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
// O(logn) | |
matrix quick_power(matrix a,int n){ | |
matrix result=I; | |
while (n){ | |
if (n&1) result=multi(result,a); | |
n>>=1; | |
a=multi(a,a); | |
} | |
return result; | |
} |
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
// quicksort average:O(nlogn) worst:O(n^2) | |
quicksort(int s[],int left,int right) | |
{ | |
int i=left,j=right,pivot; | |
pivot=s[(left+right)/2]; | |
while (i<=j){ | |
while (s[i]<pivot) i++; | |
while (s[j]>pivot) j--; | |
if (i<=j) | |
swap(&s[i],&s[j]); | |
i++;j--; | |
} | |
if (left<j) quicksort(s,left,j); | |
if (right>i) quicksort(s,i,right); | |
} |
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
// selection_sort O(n^2) | |
selection_sort(int s[],n) | |
{ | |
int i,j,min; | |
for (i=0;i<n-1;i++){ | |
min=i; | |
for (j=i+1;j<n;j++) | |
if (s[j]<s[min]) min=j; | |
swap(&s[i],&s[min]); | |
} | |
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment