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September 3, 2018 16:37
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An overkill Prolog solution to the Jindosh riddle in Dishonored 2
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exists(A, list(A, _, _, _, _)). | |
exists(A, list(_, A, _, _, _)). | |
exists(A, list(_, _, A, _, _)). | |
exists(A, list(_, _, _, A, _)). | |
exists(A, list(_, _, _, _, A)). | |
rightOf(R, L, list(L, R, _, _, _)). | |
rightOf(R, L, list(_, L, R, _, _)). | |
rightOf(R, L, list(_, _, L, R, _)). | |
rightOf(R, L, list(_, _, _, L, R)). | |
leftOf(L, R, list(L, R, _, _, _)). | |
leftOf(L, R, list(_, L, R, _, _)). | |
leftOf(L, R, list(_, _, L, R, _)). | |
leftOf(L, R, list(_, _, _, L, R)). | |
middle(A, list(_, _, A, _, _)). | |
first(A, list(A, _, _, _, _)). | |
nextTo(A, B, list(B, A, _, _, _)). | |
nextTo(A, B, list(_, B, A, _, _)). | |
nextTo(A, B, list(_, _, B, A, _)). | |
nextTo(A, B, list(_, _, _, B, A)). | |
nextTo(A, B, list(A, B, _, _, _)). | |
nextTo(A, B, list(_, A, B, _, _)). | |
nextTo(A, B, list(_, _, A, B, _)). | |
nextTo(A, B, list(_, _, _, A, B)). | |
%% name, color, city, drink, heirloom | |
jindosh(Guests) :- | |
exists(guest(finch, blue, _, _, _), Guests), | |
first(guest(winslow, _, _, _, _), Guests), | |
nextTo(guest(winslow, _, _, _, _), guest(_, green, _, _, _), Guests), | |
leftOf(guest(_, red, _, _, _), guest(_, white, _, _, _), Guests), | |
exists(guest(_, red, _, wine, _), Guests), | |
exists(guest(_, purple, dabokva, _, _), Guests), | |
nextTo(guest(_, _, _, _, ring), guest(_, _, dabokva, _, _), Guests), | |
exists(guest(contee, _, _, _, war_medal), Guests), | |
exists(guest(_, _, karnaca, _, bird_pendant), Guests), | |
nextTo(guest(_, _, _, _, diamond), guest(_, _, dunwall, _, _), Guests), | |
nextTo(guest(_, _, dunwall, _, _), guest(_, _, _, rum, _), Guests), | |
exists(guest(marcolla, _, _, whiskey, _), Guests), | |
exists(guest(_, _, baleton, absinthe, _), Guests), | |
middle(guest(_, _, _, beer, _), Guests), | |
exists(guest(natsiou, _, fraeport, _, _), Guests), | |
exists(guest(_, _, _, _, snuff_tin), Guests). |
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