othellocheck.js

function Putable(board, x, y, turn){
    var count = 0;
    for(var i = -1; i <= 1; i++){
    for(var j = -1; j <= 1; j++){
        if(i == 0 && j == 0) continue;
        if(board[y + i][x + j] == 3 - turn){
            var k = i;
            var l = j;
            var incount = 0;
            while(1){
                if(board[y + k][x + l] != 3 - turn){
                    if(board[y + k][x + l] == turn)
                        count += incount;
                    break;
                }   
                else{
                    incount++;
                    k += i;
                    l += j;
                }   
            }   
        }   
    }   
    }   
    if(count > 0) return true;
    else return false;
}