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Balanced Brackets using Segment Tree - BRCKTS in C++
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#include <iostream> | |
#include <cmath> | |
#include <algorithm> | |
using namespace std; | |
class Node { | |
public: | |
int needLeft; | |
int needRight; | |
Node(){ | |
needLeft = 0; | |
needRight = 0; | |
} | |
}; | |
void construct(string arr,Node tree[], int index, int start, int end){ | |
int mid,newMatches; | |
if(start == end){ | |
if(arr[start] == '('){ | |
tree[index].needRight = 1; | |
} | |
else{ | |
tree[index].needLeft = 1; | |
} | |
} | |
else{ | |
mid = (start+end)/2; | |
construct(arr,tree,2*index,start,mid); | |
construct(arr,tree,(2*index)+1,mid+1,end); | |
newMatches = min(tree[2*index].needRight,tree[(2*index)+1].needLeft); | |
tree[index].needLeft = tree[2*index].needLeft + tree[(2*index)+1].needLeft - newMatches; | |
tree[index].needRight = tree[2*index].needRight + tree[(2*index)+1].needRight - newMatches; | |
} | |
} | |
void modify(Node tree[], int index, int startIndex, int start, int end){ | |
int mid,newMatches; | |
if(start == end){ | |
if(tree[startIndex].needLeft == 1){ | |
tree[startIndex].needLeft = 0; | |
tree[startIndex].needRight = 1; | |
} | |
else{ | |
tree[startIndex].needLeft = 1; | |
tree[startIndex].needRight = 0; | |
} | |
return; | |
} | |
else{ | |
mid = (start+end)/2; | |
if(index <= mid){ | |
modify(tree, index, 2*startIndex, start, mid); | |
} | |
else{ | |
modify(tree, index, (2*startIndex)+1, mid+1, end); | |
} | |
newMatches = min(tree[2*startIndex].needRight,tree[(2*startIndex)+1].needLeft); | |
tree[startIndex].needLeft = tree[2*startIndex].needLeft + tree[(2*startIndex)+1].needLeft - newMatches; | |
tree[startIndex].needRight = tree[2*startIndex].needRight + tree[(2*startIndex)+1].needRight - newMatches; | |
} | |
} | |
int main() { | |
//For Fast IO | |
ios_base::sync_with_stdio(false); | |
cin.tie(NULL); | |
int n,height,i,testcase,m,k,operation; | |
string arr; | |
for(testcase=1; testcase<=10; testcase++){ | |
cin >> n; | |
cin >> arr; | |
height = int(ceil(log(n)/log(2))); | |
Node tree[int(pow(2,height+1))]; | |
construct(arr,tree,1,0,n-1); | |
cout<<"Test "<<testcase<<":"<<endl; | |
cin >> m; | |
for(operation=1; operation<=m; operation++){ | |
cin >> k; | |
if(k == 0){ | |
if(tree[1].needLeft == 0 && tree[1].needRight == 0){ | |
cout<<"YES"<<endl; | |
} | |
else{ | |
cout<<"NO"<<endl; | |
} | |
} | |
else{ | |
modify(tree,k-1,1,0,n-1); | |
} | |
} | |
} | |
return 0; | |
} |
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